CGS e.s. unit to Kiloampere
CGS ESU
kA
Conversion History
| Conversion | Reuse | Delete |
|---|---|---|
1 CGS ESU (CGS e.s. unit) → 3.335641e-13 kA (Kiloampere) Just now |
Quick Reference Table (CGS e.s. unit to Kiloampere)
| CGS e.s. unit (CGS ESU) | Kiloampere (kA) |
|---|---|
| 1 | 0.0000000000003335641 |
| 10 | 0.000000000003335641 |
| 100 | 0.00000000003335641 |
| 1,000,000 | 0.0000003335641 |
| 1,000,000,000 | 0.0003335641 |
| 3,000,000,000 | 0.0010006923 |
About CGS e.s. unit (CGS ESU)
The CGS electrostatic unit (CGS e.s. unit) of current equals approximately 3.335641×10⁻¹⁰ amperes, identical to the statampere or ESU of current. In the CGS electrostatic subsystem, current is defined as statcoulombs per second, giving one CGS e.s. unit per second of charge flow. The CGS-ESU system places Coulomb s law in a clean constant-free form but produces cumbersome dimensions for magnetic quantities. It was used in early electrostatics, cathode-ray tube physics, and vacuum science. All modern work uses SI. The factor 1/c (in CGS cm/s) converts ESU current to SI amperes.
1 CGS e.s. unit ≈ 3.336×10⁻¹⁰ A. A 1 A current equals about 3×10⁹ CGS e.s. units — illustrating the enormous scale difference between the ESU and SI systems.
About Kiloampere (kA)
The kiloampere (kA) equals one thousand amperes and appears where extremely high currents are generated or measured. A typical lightning bolt carries a peak current of 20–30 kA, though extreme strokes can exceed 200 kA. Industrial arc furnaces melting steel draw 50–100 kA through graphite electrodes. Aluminum electrolysis cells in smelters operate at 150–500 kA of continuous DC current per pot. Rail electromagnetic launchers pulse at hundreds of kiloamperes. Resistance spot welding uses 5–30 kA pulses lasting milliseconds to join metal sheets.
A typical lightning bolt peaks at 20–30 kA. Aluminum smelting cells run continuously at 150–300 kA of electrolysis current.
CGS e.s. unit – Frequently Asked Questions
Why is the CGS e.s. unit so different in magnitude from the CGS e.m. unit?
The e.m. unit equals 10 A while the e.s. unit equals 3.3 × 10⁻¹⁰ A — a ratio of about 3 × 10¹⁰, which is the speed of light in cm/s. This enormous factor reflects the fundamental relationship c² = 1/(ε₀μ₀). The two systems were designed to simplify different sets of equations, and the speed of light is the price of bridging them.
What made the CGS electrostatic system useful for early vacuum physics?
In vacuum tubes and cathode ray experiments, electrostatic forces dominate — no magnetic materials, no currents in bulk conductors. The ESU system made Coulomb's law beautifully simple: F = q₁q₂/r² with no constants. For computing electron trajectories in early TV tubes and oscilloscopes, this simplicity was genuinely helpful.
How did early CRT televisions use electrostatic units in beam deflection design?
Early cathode ray tubes used electrostatic deflection plates to steer the electron beam. Engineers working in CGS-ESU could calculate beam deflection angles directly from plate voltage and geometry using Coulomb's law without extra constants. The tiny ESU currents matched the actual beam currents (microamperes), making the numbers more intuitive than working in amperes for these minuscule electron flows.
How do I know if an old paper is using CGS e.s. or CGS e.m. units?
Check the context and the magnitude of numbers. If currents are tiny numbers where you would expect amperes, it is ESU. If they are 1/10 of expected ampere values, it is EMU. Good papers state which system they use, but many older ones do not. The equations themselves also differ — look for factors of c or 4π.
Could the CGS electrostatic system handle magnetic phenomena?
Technically yes, but clumsily. In pure CGS-ESU, the magnetic field has dimensions involving the speed of light, and equations for inductance and magnetic force become awkward. This is exactly why the Gaussian hybrid was invented — it uses ESU for electric quantities and EMU for magnetic ones, giving clean equations for both.
Kiloampere – Frequently Asked Questions
How does a spot welder push 10,000 amps through two sheets of metal?
A spot welder uses a large step-down transformer: high voltage at low current on the primary becomes very low voltage (1–2 V) at enormous current (5–30 kA) on the secondary. The copper electrode tips concentrate this current into a small spot, melting the metal in milliseconds. Total power is only 10–60 kW — it is the concentration that does the work.
What happens to a wire if you put a kiloampere through it?
A typical 14 AWG house wire rated for 15 A would vaporise almost instantly at 1 kA — the I²R heating would melt copper in milliseconds. Industrial busbars carrying kiloamperes are massive rectangular copper or aluminum bars, sometimes water-cooled, with cross-sections of 10–100 cm² to keep current density manageable.
How much current does a lightning bolt actually carry?
A typical negative cloud-to-ground stroke peaks at 20–30 kA for about 1–2 microseconds. Positive lightning (rarer, about 5% of strikes) can exceed 300 kA. The total charge transferred is only 1–5 coulombs because the pulse is so brief — enormous current, tiny duration.
Why do aluminum smelters need hundreds of kiloamperes?
Aluminum oxide dissolved in molten cryolite at 960 degrees C requires direct electrolytic reduction to separate aluminum metal. Each smelting pot runs at 4–5 V but needs 150–500 kA because the electrochemical reaction requires massive charge transfer. A single smelter may consume 1–2 GW — as much as a small city.
What protects electrical systems from kiloampere fault currents?
Circuit breakers rated for 10–200 kA interrupting capacity use arc-quenching chambers to extinguish the plasma arc that forms when contacts open under fault current. High-rupture-capacity (HRC) fuses have sand-filled ceramic bodies that absorb the arc energy. Without these devices, a short circuit on a utility feed would weld everything in the panel into slag.