Milliampere to Watt per volt

mA

1 mA

W/V

0.001 W/V

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Quick Reference Table (Milliampere to Watt per volt)

Milliampere (mA)Watt per volt (W/V)
10.001
50.005
200.02
1000.1
5000.5
1,0001
2,0002

About Milliampere (mA)

The milliampere (mA) equals one thousandth of an ampere (10⁻³ A) and is the practical unit for most consumer electronics and lighting circuits. USB 2.0 ports supply up to 500 mA; USB-C Power Delivery can reach 5,000 mA (5 A). A standard 5 mm indicator LED operates at 10–20 mA; mid-power LED drivers supply 100–350 mA. Human perception of electric shock begins near 1 mA; currents above 10 mA cause involuntary muscle contraction, and above 100 mA can be lethal. Wireless sensors, earphones, and small motors typically draw single-digit to low-hundreds of milliamperes.

A USB 2.0 port provides up to 500 mA for charging. A standard 5 mm indicator LED operates at around 20 mA.

About Watt per volt (W/V)

The watt per volt (W/V) equals one ampere, derived from the power relationship P = IV rearranged as I = P/V. A device consuming 60 W at 120 V draws 0.5 W/V = 0.5 A. The W/V form is most useful when calculating branch currents from known power ratings and supply voltages — for appliance load calculations, transformer secondary currents, or power budget analysis on a circuit board. Numerically identical to the ampere, it provides an alternative view emphasising the power-per-volt character of current and is common in power electronics and electrical installation design.

A 100 W light bulb on a 230 V supply draws approximately 0.43 W/V. A 60 W laptop adapter at 20 V delivers 3 W/V to the device.


Milliampere – Frequently Asked Questions

The danger thresholds for 50/60 Hz AC are roughly: 1 mA (tingling), 10–20 mA (muscle lock — you cannot let go), 75–100 mA (ventricular fibrillation), and 200+ mA (cardiac arrest and burns). DC is somewhat less dangerous at the same current. Duration matters enormously — 100 mA for 1 second is more lethal than 100 mA for 10 ms.

Battery capacity is rated in milliampere-hours (mAh), not milliamps. A 4,000 mAh battery holds 4,000 mA for one hour (or 2,000 mA for two hours). The charger delivers 2 A (2,000 mA) of current, and it takes about 2 hours to fill that 4,000 mAh battery from empty.

A wireless earbud draws 5–15 mA during playback. A TV remote uses about 10 mA when pressing a button. An LED nightlight consumes 20–50 mA. A smoke detector in standby draws 10–30 μA (0.01–0.03 mA) — so low it runs on a 9V battery for years.

Standard 5 mm indicator LEDs were designed around a 20 mA operating point — bright enough to see clearly, low enough to avoid overheating the tiny die. All datasheet specs (luminous intensity, color, forward voltage) are measured at this "test current." High-power LEDs use 350 mA or 700 mA as their reference instead.

Milliamp-hours measure charge capacity; milliamps measure current flow rate. A 2,000 mAh battery can deliver 2,000 mA for 1 hour, or 200 mA for 10 hours, or 20 mA for 100 hours — current times time equals capacity. Dividing mAh by mA gives approximate runtime in hours.

Watt per volt – Frequently Asked Questions

When sizing circuits, electricians know the appliance power (watts from the nameplate) and the supply voltage (120 V or 230 V). Dividing watts by volts gives the current in amps — which is what determines wire gauge and breaker size. "1,800 W ÷ 120 V = 15 A, so I need a 20 A circuit" is daily electrician math.

No — product labels list watts, volts, and amps separately. The W/V expression lives in textbooks and engineering calculations. But every time you read "1,500 W, 120 V" on a space heater and mentally divide to get 12.5 A, you are computing watts per volt without calling it that.

Only approximately. For AC, real power (watts) = V × I × power factor. So I = W / (V × PF). A motor rated at 1,000 W with a power factor of 0.85 on 230 V actually draws 1,000 / (230 × 0.85) = 5.1 A, not the 4.35 A that simple W/V would suggest. Always account for power factor in AC circuits.

USB PD negotiates voltage levels (5 V, 9 V, 15 V, 20 V) and maximum power (up to 240 W). Dividing the negotiated power by voltage gives the cable current: 100 W at 20 V = 5 A, requiring a 5 A rated cable. At 5 V the same 100 W would need 20 A — which is why PD uses higher voltages.

From P = IV and V = IR, you get I = P/V = V/R = P^(1/2)/R^(1/2). The W/V form is just one of many equivalent expressions for current. Which one you use depends on what you know: power and voltage gives W/V, voltage and resistance gives V/R (Ohm's law directly).

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