Watt per volt to ESU of current
W/V
ESU
Conversion History
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Quick Reference Table (Watt per volt to ESU of current)
| Watt per volt (W/V) | ESU of current (ESU) |
|---|---|
| 0.1 | 299,792,460 |
| 1 | 2,997,924,600 |
| 5 | 14,989,623,000 |
| 10 | 29,979,246,000 |
| 20 | 59,958,492,000 |
| 100 | 299,792,460,000 |
Results rounded to a maximum of 8 significant figures
About Watt per volt (W/V)
The watt per volt (W/V) equals one ampere, derived from the power relationship P = IV rearranged as I = P/V. A device consuming 60 W at 120 V draws 0.5 W/V = 0.5 A. The W/V form is most useful when calculating branch currents from known power ratings and supply voltages — for appliance load calculations, transformer secondary currents, or power budget analysis on a circuit board. Numerically identical to the ampere, it provides an alternative view emphasising the power-per-volt character of current and is common in power electronics and electrical installation design.
A 100 W light bulb on a 230 V supply draws approximately 0.43 W/V. A 60 W laptop adapter at 20 V delivers 3 W/V to the device.
About ESU of current (ESU)
The electrostatic unit of current (ESU, also called the statampere) equals approximately 3.335640952×10⁻¹⁰ amperes under the traditional CGS-to-SI mapping used by this converter. It is the current unit of the CGS electrostatic system (CGS-ESU), in which Coulomb's law is written without a permittivity constant and electric charge is measured in statcoulombs (franklins). One statampere is the flow of one statcoulomb per second. The traditional mapping is 1 A = (c/10) statamperes, using the numerical speed of light c = 29,979,245,800 in cm/s, so 1 A maps to 2,997,924,580 statamperes. This is a conventional mapping, not a claim of an exact physical conversion to the post-2019 SI. The CGS-ESU system was used in early electrostatics and vacuum tube physics but is obsolete in applied engineering.
1 ESU of current ≈ 3.336×10⁻¹⁰ A — an extraordinarily small current. One ordinary ampere equals approximately 3×10⁹ ESU.
Watt per volt – Frequently Asked Questions
Why would an electrician think in watts per volt?
When sizing circuits, electricians know the appliance power (watts from the nameplate) and the supply voltage (120 V or 230 V). Dividing watts by volts gives the current in amps — which is what determines wire gauge and breaker size. "1,800 W ÷ 120 V = 15 A, so I need a 20 A circuit" is daily electrician math.
Is watts per volt ever written on any product label?
No — product labels list watts, volts, and amps separately. The W/V expression lives in textbooks and engineering calculations. But every time you read "1,500 W, 120 V" on a space heater and mentally divide to get 12.5 A, you are computing watts per volt without calling it that.
Does the watts-per-volt calculation work for AC power?
Only approximately. For AC, real power (watts) = V × I × power factor. So I = W / (V × PF). A motor rated at 1,000 W with a power factor of 0.85 on 230 V actually draws 1,000 / (230 × 0.85) = 5.1 A, not the 4.35 A that simple W/V would suggest. Always account for power factor in AC circuits.
How does watts per volt help with USB power delivery calculations?
USB PD negotiates voltage levels (5 V, 9 V, 15 V, 20 V) and maximum power (up to 240 W). Dividing the negotiated power by voltage gives the cable current: 100 W at 20 V = 5 A, requiring a 5 A rated cable. At 5 V the same 100 W would need 20 A — which is why PD uses higher voltages.
What is the relationship between watts per volt and Ohm's law?
From P = IV and V = IR, you get I = P/V = V/R = P^(1/2)/R^(1/2). The W/V form is just one of many equivalent expressions for current. Which one you use depends on what you know: power and voltage gives W/V, voltage and resistance gives V/R (Ohm's law directly).
ESU of current – Frequently Asked Questions
Why is the ESU of current so absurdly small compared to an ampere?
The ESU system was designed to make Coulomb's electrostatic law simple (no constants), which means its charge unit (the statcoulomb) is tiny relative to the coulomb. Since current is charge per time, the statampere inherits that smallness. Under the traditional mapping used here, one ampere maps to 2,997,924,580 statamperes — the numerical speed of light in cm/s divided by 10. In the reverse direction, multiply the statampere value by 10/c, or divide by 2,997,924,580, to obtain amperes.
What is a statampere and is it the same as an ESU of current?
Yes. Statampere, ESU of current, CGS electrostatic current, franklin per second and Gaussian current share the same current scale. This converter uses the same traditional mapping for all five names: 1 A maps to 2,997,924,580 statamperes. "Statampere" is the named form; "ESU of current" is the descriptive form. The "stat-" prefix comes from "electrostatic," just as the "ab-" prefix in the EMU system comes from "absolute."
Did the 2019 SI redefinition change the statampere?
No. The statampere remains one statcoulomb per second in the CGS system. What changed was the SI ampere: in 2019 it was redefined by fixing the elementary charge, replacing its earlier force-based definition. Vacuum permeability and permittivity are consequently no longer exact SI constants, so physical conversions between CGS electrical units and modern SI involve measured values and uncertainty. This converter retains the pre-2019 mapping of 1 A to 2,997,924,580 statamperes for consistent reference conversions; it does not apply modern measured corrections.
What role did the ESU system play in the discovery that light is electromagnetic?
When Weber and Kohlrausch measured the ratio of ESU to EMU charge in 1856, they got a number suspiciously close to the speed of light — about 3×10¹⁰ cm/s. Maxwell realized this was no coincidence: it meant electromagnetic disturbances propagate at light speed, proving light itself is an electromagnetic wave. A unit conversion exercise led to one of the greatest discoveries in physics.
What practical problem did the ESU system solve for 19th-century telegraph engineers?
Telegraph cables behaved like long capacitors — charge stored along the line distorted signals over transatlantic distances. The ESU system, built around Coulomb's law, made capacitance calculations straightforward: no permittivity constants, just geometry and charge. William Thomson (Lord Kelvin) used ESU-based analysis to diagnose and fix signal distortion on the first transatlantic telegraph cables in the 1860s.
Why were electrostatic and electromagnetic measurements historically done in separate labs?
Electrostatic experiments (rubbing rods, Leyden jars, spark gaps) involved high voltages and tiny charges, while electromagnetic work (coils, galvanometers, telegraph lines) involved low voltages and large currents. The equipment, techniques, and even the physicists were different. Each community built units natural to their measurements — ESU for electrostatics, EMU for electromagnetics — and it took decades after Maxwell to unify them into one coherent SI framework.