Weber per henry to Kiloampere
Wb/H
kA
Conversion History
| Conversion | Reuse | Delete |
|---|---|---|
1 Wb/H (Weber per henry) → 0.001 kA (Kiloampere) Just now |
Quick Reference Table (Weber per henry to Kiloampere)
| Weber per henry (Wb/H) | Kiloampere (kA) |
|---|---|
| 0.1 | 0.0001 |
| 1 | 0.001 |
| 5 | 0.005 |
| 10 | 0.01 |
| 20 | 0.02 |
| 100 | 0.1 |
About Weber per henry (Wb/H)
The weber per henry (Wb/H) equals one ampere, derived from inductance: the magnetic flux Φ stored in an inductor equals inductance L times current I (Φ = L·I), so I = Φ/L = Wb/H. This form appears in electromagnetic field theory and inductor design where engineers compute the current required to establish a given magnetic flux in a core. One weber of flux in a one-henry inductor corresponds to exactly one ampere of magnetising current. The Wb/H notation is common in transformer and motor design calculations, magnetic circuit analysis, and advanced EMC engineering where field and circuit quantities must be reconciled.
A 1 H inductor carrying 5 A stores 5 Wb of magnetic flux — expressed as 5 Wb/H. Power transformer core saturation analysis links flux density to Wb/H magnetising current.
About Kiloampere (kA)
The kiloampere (kA) equals one thousand amperes and appears where extremely high currents are generated or measured. A typical lightning bolt carries a peak current of 20–30 kA, though extreme strokes can exceed 200 kA. Industrial arc furnaces melting steel draw 50–100 kA through graphite electrodes. Aluminum electrolysis cells in smelters operate at 150–500 kA of continuous DC current per pot. Rail electromagnetic launchers pulse at hundreds of kiloamperes. Resistance spot welding uses 5–30 kA pulses lasting milliseconds to join metal sheets.
A typical lightning bolt peaks at 20–30 kA. Aluminum smelting cells run continuously at 150–300 kA of electrolysis current.
Weber per henry – Frequently Asked Questions
Why would a transformer designer think in webers per henry?
When designing a transformer, you start with the required flux (webers) to transfer power at a given voltage and frequency. The core's inductance (henries) is set by geometry and material. Dividing flux by inductance gives the magnetising current that must flow — and if it is too high, the core saturates and the transformer overheats.
What is a weber in practical terms?
One weber is the magnetic flux that, when reduced to zero in one second, induces one volt in a single-turn coil. A small transformer core might carry 0.001 Wb (1 mWb) of peak flux. The Earth's magnetic field through a 1 m² loop is about 50 μWb. One weber is actually an enormous amount of flux in everyday terms.
What happens when the Wb/H calculation shows too much current?
If the calculated magnetising current (Wb/H) exceeds design limits, the core is approaching magnetic saturation. The inductance drops sharply, current spikes further, and the inductor or transformer overheats. Solutions include using a larger core, higher-permeability material, an air gap, or reducing the operating flux density.
How does core saturation relate to the Wb/H ratio?
Every magnetic core has a saturation flux density (e.g., 1.5 T for silicon steel, 0.3 T for ferrite). When flux approaches this limit, permeability collapses, inductance plummets, and Wb/H (current) shoots up. Power supply designers must ensure peak flux stays 20–30% below saturation under worst-case conditions.
How does an air gap in an inductor core change the Wb/H calculation?
An air gap dramatically increases the reluctance of the magnetic circuit, which lowers inductance (H) for the same core geometry. For a given flux (Wb), the magnetising current (Wb/H) increases — but the core is far harder to saturate. Power supply designers deliberately add 0.1–1 mm air gaps to ferrite cores so the inductor can handle higher peak currents without the flux density hitting saturation limits.
Kiloampere – Frequently Asked Questions
How does a spot welder push 10,000 amps through two sheets of metal?
A spot welder uses a large step-down transformer: high voltage at low current on the primary becomes very low voltage (1–2 V) at enormous current (5–30 kA) on the secondary. The copper electrode tips concentrate this current into a small spot, melting the metal in milliseconds. Total power is only 10–60 kW — it is the concentration that does the work.
What happens to a wire if you put a kiloampere through it?
A typical 14 AWG house wire rated for 15 A would vaporise almost instantly at 1 kA — the I²R heating would melt copper in milliseconds. Industrial busbars carrying kiloamperes are massive rectangular copper or aluminum bars, sometimes water-cooled, with cross-sections of 10–100 cm² to keep current density manageable.
How much current does a lightning bolt actually carry?
A typical negative cloud-to-ground stroke peaks at 20–30 kA for about 1–2 microseconds. Positive lightning (rarer, about 5% of strikes) can exceed 300 kA. The total charge transferred is only 1–5 coulombs because the pulse is so brief — enormous current, tiny duration.
Why do aluminum smelters need hundreds of kiloamperes?
Aluminum oxide dissolved in molten cryolite at 960 degrees C requires direct electrolytic reduction to separate aluminum metal. Each smelting pot runs at 4–5 V but needs 150–500 kA because the electrochemical reaction requires massive charge transfer. A single smelter may consume 1–2 GW — as much as a small city.
What protects electrical systems from kiloampere fault currents?
Circuit breakers rated for 10–200 kA interrupting capacity use arc-quenching chambers to extinguish the plasma arc that forms when contacts open under fault current. High-rupture-capacity (HRC) fuses have sand-filled ceramic bodies that absorb the arc energy. Without these devices, a short circuit on a utility feed would weld everything in the panel into slag.