Foot-pound to Gigajoule

American automotive engineering adopted foot-pounds because it was the natural imperial torque unit — one pound-force at one foot from the crankshaft center. The convention became entrenched through SAE standards, shop manuals, and dyno testing. Converting to newton-meters (1 ft·lb ≈ 1.3558 N·m) is straightforward, but the entire US aftermarket ecosystem — torque wrenches, spec sheets, and mechanics' training — runs on foot-pounds.

Diesel engines compress air to much higher ratios (15–22:1 vs 8–12:1 for petrol), creating higher cylinder pressures that push harder on the piston — more force per stroke means more torque. But diesels rev lower (typically 4,000–4,500 RPM max vs 6,000–8,000 RPM) because the heavier rotating assembly and slower combustion limit speed. Since horsepower = torque × RPM / 5,252, the lower RPM ceiling caps peak horsepower despite the torque advantage.

Horsepower = torque (ft·lb) × RPM / 5,252. The constant 5,252 comes from unit conversion: 1 HP = 33,000 ft·lb/min, and 33,000 / (2π) ≈ 5,252. This means torque and horsepower curves on a dyno chart always intersect at exactly 5,252 RPM. Below that speed, torque is numerically higher; above it, horsepower is. This is why trucks optimize for low-RPM torque (pulling force) while sportscars chase high-RPM horsepower (speed).

Most passenger cars specify 80–100 ft·lb for wheel lug nuts; light trucks and SUVs call for 100–140 ft·lb; and heavy-duty trucks may require 450–500 ft·lb. Under-torquing risks the wheel coming loose, while over-torquing can warp brake rotors or snap studs. A calibrated torque wrench — not an impact gun alone — is the safe approach.

Muzzle energy in foot-pounds measures the kinetic energy of a bullet leaving the barrel. A 9 mm pistol produces about 350–400 ft·lb, a .45 ACP about 350–500 ft·lb, and a .308 rifle about 2,600–2,800 ft·lb. While muzzle energy is one factor in terminal performance, bullet construction, sectional density, and shot placement matter at least as much in real-world ballistics.

In cold-climate countries, 30–60 GJ per year is common for heating and hot water. A well-insulated modern home in Germany might use 20 GJ; a drafty older home in Canada might use 100+ GJ. Australians use about 40 GJ/year on average. Each gigajoule costs roughly $8–$15 depending on local gas prices.

One tonne of coal holds roughly 24–30 GJ depending on grade. One tonne of crude oil contains about 42–44 GJ. One tonne of LNG holds roughly 54 GJ. One tonne of dry firewood stores about 16 GJ. These figures explain why oil and gas are preferred for transport — they pack more gigajoules per kilogram than solid fuels.

One gigajoule equals 277.78 kWh. At an average electricity price of $0.15/kWh, one gigajoule of electrical energy costs about $42. The same gigajoule from natural gas costs $8–15. This price gap is the main reason gas boilers remain popular for heating in countries with cheap pipeline gas.

A single-aisle jet like the Boeing 737-800 burns about 10–12 GJ per flight hour. A six-hour transatlantic flight on a wide-body aircraft can consume 300–400 GJ of jet fuel. The entire global aviation industry uses roughly 12 billion gigajoules of fuel per year — about 3% of total world energy consumption.

At 2,000 kcal/day (8.4 MJ/day), a person consumes about 3.07 GJ of food energy per year. Over 80 years, that is roughly 245 GJ — equivalent to about 6,000 liters of petrol. Your entire lifetime food energy would fit in a medium-sized fuel tanker, which is a humbling thought.