Foot-pound to Calorie (nutritional)
ft-lb
Cal
Conversion History
| Conversion | Reuse | Delete |
|---|---|---|
| No conversion history to show. | ||
Quick Reference Table (Foot-pound to Calorie (nutritional))
| Foot-pound (ft-lb) | Calorie (nutritional) (Cal) |
|---|---|
| 1 | 0.00032404827 |
| 12 | 0.0038885792 |
| 50 | 0.016202413 |
| 100 | 0.032404827 |
| 200 | 0.064809653 |
| 400 | 0.12961931 |
| 600 | 0.19442896 |
Results rounded to a maximum of 8 significant figures
About Foot-pound (ft-lb)
The foot-pound (ft·lb) is the standard unit of torque and mechanical energy in the US customary system, equal to approximately 1.35582 joules. It represents the work done by a force of one pound-force through a displacement of one foot. Engine torque in American automotive engineering is quoted exclusively in foot-pounds (e.g., a V8 pickup truck producing 400 ft·lb). Bolt torque specifications in the US use foot-pounds for larger fasteners. One foot-pound equals 12 inch-pounds.
A typical car engine produces 150–400 ft·lb of torque. A cylinder head bolt on an engine is typically torqued to 60–90 ft·lb.
About Calorie (nutritional) (Cal)
A nutritional or food Calorie (Cal) means one kilocalorie (kcal), not one small laboratory calorie. This converter follows the FAO food-energy convention of 1 kcal = 4.184 kJ, or 4,184 joules. The nutritional Calorie and nutritional kilocalorie selections therefore represent the same energy scale. One food Calorie also equals 1,000 small thermochemical calories (cal th). It is not the small International Table calorie of 4.1868 J.
A food item labelled "90 Calories" contains 90 kcal, or 376,560 joules, using this converter's food-energy convention.
Foot-pound – Frequently Asked Questions
Why is engine torque measured in foot-pounds in the US?
American automotive engineering adopted foot-pounds because it was the natural imperial torque unit — one pound-force at one foot from the crankshaft center. The convention became entrenched through SAE standards, shop manuals, and dyno testing. Converting to newton-meters (1 ft·lb ≈ 1.3558 N·m) is straightforward, but the entire US aftermarket ecosystem — torque wrenches, spec sheets, and mechanics' training — runs on foot-pounds.
Why do diesel engines produce more torque but less horsepower than petrol engines at the same displacement?
Diesel engines compress air to much higher ratios (15–22:1 vs 8–12:1 for petrol), creating higher cylinder pressures that push harder on the piston — more force per stroke means more torque. But diesels rev lower (typically 4,000–4,500 RPM max vs 6,000–8,000 RPM) because the heavier rotating assembly and slower combustion limit speed. Since horsepower = torque × RPM / 5,252, the lower RPM ceiling caps peak horsepower despite the torque advantage.
What is the torque-to-horsepower relationship and why does it cross at 5,252 RPM?
Horsepower = torque (ft·lb) × RPM / 5,252. The constant 5,252 comes from unit conversion: 1 HP = 33,000 ft·lb/min, and 33,000 / (2π) ≈ 5,252. This means torque and horsepower curves on a dyno chart always intersect at exactly 5,252 RPM. Below that speed, torque is numerically higher; above it, horsepower is. This is why trucks optimize for low-RPM torque (pulling force) while sportscars chase high-RPM horsepower (speed).
What foot-pound torque values are typical for car lug nuts?
Most passenger cars specify 80–100 ft·lb for wheel lug nuts; light trucks and SUVs call for 100–140 ft·lb; and heavy-duty trucks may require 450–500 ft·lb. Under-torquing risks the wheel coming loose, while over-torquing can warp brake rotors or snap studs. A calibrated torque wrench — not an impact gun alone — is the safe approach.
How does foot-pound muzzle energy relate to firearm stopping power?
Muzzle energy in foot-pounds measures the kinetic energy of a bullet leaving the barrel. A 9 mm pistol produces about 350–400 ft·lb, a .45 ACP about 350–500 ft·lb, and a .308 rifle about 2,600–2,800 ft·lb. While muzzle energy is one factor in terminal performance, bullet construction, sectional density, and shot placement matter at least as much in real-world ballistics.
Calorie (nutritional) – Frequently Asked Questions
Why is a food calorie actually a kilocalorie?
In the late 19th century, nutritionists adopted the kilocalorie as the practical unit for food energy but dropped the "kilo" prefix in everyday speech. A banana labelled "90 calories" actually contains 90 kilocalories (90,000 small calories). Some labels use a capital "C" (Calorie) to distinguish it from the small calorie, but this convention is inconsistently applied and remains a source of confusion worldwide.
What is the difference between cal and kcal on a nutrition label?
Lowercase cal denotes a small calorie; a kilocalorie is 1,000 small calories of the same variant. A food Calorie (Cal), however, already means one kilocalorie. In this converter, 200 food Calories = 200 nutritional kcal = 836.8 kJ. The separate small thermochemical calorie selection uses 4.184 J per cal th, while each nutritional selection uses 4,184 J per Cal or kcal.
How many nutritional calories does the average person need per day?
This converter does not determine a daily energy requirement; it only converts a supplied energy quantity. For example, 2,000 food Calories means 2,000 nutritional kcal, or 8,368 kJ, using the selected convention. That conversion example is not a personal intake recommendation.
Why do some countries use kilojoules instead of calories on food labels?
Kilojoules are an SI energy unit, while kilocalories remain common for food-energy quantities. For the food-energy convention used here, multiply kcal by 4.184 to get kJ, or divide kJ by 4.184 to get kcal. For example, 2,000 kcal = 8,368 kJ. The food Calorie (Cal) and nutritional kcal selections use the same conversion factor.
How was the nutritional calorie originally measured?
Wilbur Atwater and colleagues in the 1890s used bomb calorimeters to burn food samples and measure heat released. They established that carbohydrates yield ~4 kcal/g, protein ~4 kcal/g, and fat ~9 kcal/g — the Atwater factors still printed on food labels today. Modern methods use chemical analysis and Atwater factors rather than direct calorimetry for every product.