Foot pounds-force second to Joules/second

ft·lbf/s

1 ft·lbf/s

J/s

1.35581794833508 J/s

Conversion History

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1 ft·lbf/s (Foot pounds-force second) → 1.35581794833508 J/s (Joules/second)

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Quick Reference Table (Foot pounds-force second to Joules/second)

Foot pounds-force second (ft·lbf/s)Joules/second (J/s)
11.35581794833508
1013.5581794833508
100135.581794833508
200271.163589667016
550745.699871584294
1,0001,355.81794833508
5,0006,779.0897416754

About Foot pounds-force second (ft·lbf/s)

Foot pounds-force per second (ft·lbf/s) is the fundamental mechanical power unit in the US customary system, equal to approximately 1.356 watts. It is the rate of doing work when a force of one pound-force moves through one foot per second. The unit is directly related to the mechanical horsepower: one horsepower equals exactly 550 ft·lbf/s. It appears in US mechanical engineering, ballistics, and machinery design texts.

One mechanical horsepower equals 550 ft·lbf/s (~746 W). A person climbing stairs moderately expends about 200–300 ft·lbf/s of mechanical power.

About Joules/second (J/s)

Joules per second (J/s) is the dimensional expression of power in the SI system, and is exactly equivalent to the watt by definition. While "watt" is the named unit used in practice, J/s appears in physics derivations, dimensional analysis, and engineering calculations where explicit unit tracking is required. Seeing power written as J/s emphasizes the energy-per-time nature of the quantity and connects power directly to the joule and second without introducing a derived unit name.

A 100 W light bulb consumes 100 J/s of electrical energy. A person climbing stairs at moderate pace expends roughly 300 J/s of mechanical power.


Foot pounds-force second – Frequently Asked Questions

James Watt calculated that a mill horse could turn a mill wheel 144 times per hour, doing 32,572 ft·lbf of work per minute — he rounded up to 33,000 ft·lbf/min (550 ft·lbf/s) for marketing purposes. He wanted to sell steam engines by comparing them to horses, so he likely overestimated the horse to make his engines look like better value. A real horse sustains closer to 350–500 ft·lbf/s, so Watt's "1 HP" is actually more than one horse.

Power (ft·lbf/s) = Torque (ft·lbf) × RPM × 2π / 60. This is the workhorse formula (pun intended) of US mechanical engineering. For example, an engine producing 200 ft·lbf of torque at 3,000 RPM delivers 200 × 3,000 × 6.2832 / 60 = 62,832 ft·lbf/s ≈ 114 hp. The formula works because angular velocity in rad/s times torque in ft·lbf gives power directly in ft·lbf/s.

Pushing with 1 pound of force at 1 foot per second — roughly the effort of slowly sliding a light book across a table against friction. Lifting a 1-pound weight 1 foot in 1 second. Turning a doorknob with a very light touch. It's about 1.36 watts — enough to dimly light an LED. In human terms, it's almost effortless: casual walking produces about 50–80 ft·lbf/s of mechanical power, and you don't even notice.

Yes, particularly in ballistics (muzzle energy rates), mechanical testing (dynamometer output), agricultural machinery specs, and industrial equipment designed for the US market. However, even in the US, many engineering firms are switching to SI units for international compatibility. The automotive industry increasingly quotes power in both hp and kW. Aerospace has been mostly metric since the 1990s. Ft·lbf/s survives mainly in traditional mechanical and manufacturing industries.

Bullets are rated in ft·lbf of muzzle energy (not per second), but the power of a firearm is the muzzle energy divided by barrel time. A .308 rifle bullet exits with about 2,600 ft·lbf of energy over a barrel transit time of ~0.001 seconds, meaning the instantaneous power is roughly 2,600,000 ft·lbf/s (about 3,500 hp). That's why rifle recoil feels punchy — for a millisecond, you're absorbing the reaction force of a truck engine.

Joules/second – Frequently Asked Questions

In dimensional analysis and physics derivations, writing J/s keeps the units transparent — you can see exactly what's being divided and multiplied. If you're calculating power as force × velocity (N·m/s = J/s), keeping it as J/s avoids a mental leap. Students and textbook authors prefer it when teaching the concept of power, because "energy per time" is more intuitive than a named unit. Once you understand it, you switch to watts for brevity.

The SI system officially defines the watt as the named unit for power, with J/s as its definition. In metrology documents and BIPM publications, you'll see W = J/s = kg·m²/s³. Some ISO standards for calorimetry and heat flow measurements express power in J/s to maintain consistency with energy measurements also given in joules. In practice, scientific papers in thermodynamics and physical chemistry often prefer J/s for clarity.

It makes unit cancellation visible. If you know a machine delivers 500 J of work over 10 seconds, writing 500 J ÷ 10 s = 50 J/s is a complete, self-checking calculation. Converting immediately to "50 W" obscures the path. In thermodynamics, where you track joules of heat, joules of work, and joules per second of power flow, keeping J/s prevents sign and unit errors that plague students.

J/s = W = V·A = kg·m²/s³. Each form has its domain: electrical engineers think V·A, mechanical engineers think N·m/s, and physicists think kg·m²/s³. The beauty of SI is that they're all identical. A volt is a J/C, an ampere is C/s, so V·A = J/C × C/s = J/s. This chain of definitions means you can derive any electrical quantity from mass, length, time, and current.

Never — they are exactly identical by definition, with zero rounding or conversion error. 1 J/s = 1 W, always. This is unlike, say, calories per second vs. watts, where a conversion factor (4.184) introduces potential rounding issues. The equivalence is definitional, not empirical. If someone claims a difference exists, they're confusing joules per second with some other energy-per-time unit like calories per second or BTU per hour.

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